Webdriver Screenshot

Posted on

Question :

Webdriver Screenshot

When taking a screenshot using Selenium Webdriver on windows with python, the screenshot is saved directly to the path of the program, is there a way to save the .png file to a specific directory?

Answer #1:

Use driver.save_screenshot('/path/to/file') or driver.get_screenshot_as_file('/path/to/file'):

import selenium.webdriver as webdriver
import contextlib

@contextlib.contextmanager
def quitting(thing):
    yield thing
    thing.quit()

with quitting(webdriver.Firefox()) as driver:
    driver.implicitly_wait(10)
    driver.get('http://www.google.com')
    driver.get_screenshot_as_file('/tmp/google.png') 
    # driver.save_screenshot('/tmp/google.png')
Answered By: unutbu

Answer #2:

Inspired from this thread (same question for Java): Take a screenshot with Selenium WebDriver

from selenium import webdriver

browser = webdriver.Firefox()
browser.get('http://www.google.com/')
browser.save_screenshot('screenie.png')
browser.quit()
Answered By: Ran Adler

Answer #3:

Yes, we have a way to get screenshot extension of .png using python webdriver

use below code if you working in python webriver.it is very simple.

driver.save_screenshot('Dfolderfilename.png')
Answered By: Kv.senthilkumar

Answer #4:

driver.save_screenshot("path to save \screen.jpeg")
Answered By: Shaik

Answer #5:

Sure it isn’t actual right now but I faced this issue also and my way:
Looks like ‘save_screenshot’ have some troubles with creating files with space in name same time as I added randomization to filenames for escaping override.

Here I got method to clean my filename of whitespaces (How do I replace whitespaces with underscore and vice versa?):

def urlify(self, s):
    # Remove all non-word characters (everything except numbers and letters)
    s = re.sub(r"[^ws]", '', s)
    # Replace all runs of whitespace with a single dash
    s = re.sub(r"s+", '-', s)
    return s

then

driver.save_screenshot('c:\pytest_screenshots\%s' % screen_name)

where

def datetime_now(prefix):
    symbols = str(datetime.datetime.now())
    return prefix + "-" + "".join(symbols)

screen_name = self.urlify(datetime_now('screen')) + '.png'
Answered By: Vladimir Kolenov

Answer #6:

Here they asked a similar question, and the answer seems more complete, I leave the source:

How to take partial screenshot with Selenium WebDriver in python?

from selenium import webdriver
from PIL import Image
from io import BytesIO

fox = webdriver.Firefox()
fox.get('http://stackoverflow.com/')

# now that we have the preliminary stuff out of the way time to get that image :D
element = fox.find_element_by_id('hlogo') # find part of the page you want image of
location = element.location
size = element.size
png = fox.get_screenshot_as_png() # saves screenshot of entire page
fox.quit()

im = Image.open(BytesIO(png)) # uses PIL library to open image in memory

left = location['x']
top = location['y']
right = location['x'] + size['width']
bottom = location['y'] + size['height']


im = im.crop((left, top, right, bottom)) # defines crop points
im.save('screenshot.png') # saves new cropped image
Answered By: gabriel de la cruz

Answer #7:

This will take screenshot and place it in a directory of a chosen name.

import os
driver.save_screenshot(os.path.join(os.path.dirname(os.path.realpath(__file__)), 'NameOfScreenShotDirectory', 'PutFileNameHere'))
Answered By: Ger Mc

Answer #8:

You can use below function for relative path as absolute path is not a good idea to add in script

Import

import sys, os

Use code as below :

ROOT_DIR = os.path.dirname(os.path.abspath(__file__))
screenshotpath = os.path.join(os.path.sep, ROOT_DIR,'Screenshots'+ os.sep)
driver.get_screenshot_as_file(screenshotpath+"testPngFunction.png")

make sure you create the folder where the .py file is present.

os.path.join also prevent you to run your script in cross-platform like: UNIX and windows. It will generate path separator as per OS at runtime. os.sep is similar like File.separtor in java

Answered By: Shubham Jain

Leave a Reply

Your email address will not be published.