# splitting a number into the integer and decimal parts

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### Question :

splitting a number into the integer and decimal parts

Is there a pythonic way of splitting a number such as `1234.5678` into two parts `(1234, 0.5678)` i.e. the integer part and the decimal part?

``````import math
x = 1234.5678
math.modf(x) # (0.5678000000000338, 1234.0)
``````

We can use a not famous built-in function; divmod:

``````>>> s = 1234.5678
>>> i, d = divmod(s, 1)
>>> i
1234.0
>>> d
0.5678000000000338
``````

``````>>> a = 147.234
>>> a % 1
0.23400000000000887
>>> a // 1
147.0
>>>
``````

If you want the integer part as an integer and not a float, use `int(a//1)` instead. To obtain the tuple in a single passage: `(int(a//1), a%1)`

EDIT: Remember that the decimal part of a float number is approximate, so if you want to represent it as a human would do, you need to use the decimal library

``````intpart,decimalpart = int(value),value-int(value)
``````

Works for positive numbers.

This variant allows getting desired precision:

``````>>> a = 1234.5678
>>> (lambda x, y: (int(x), int(x*y) % y/y))(a, 1e0)
(1234, 0.0)
>>> (lambda x, y: (int(x), int(x*y) % y/y))(a, 1e1)
(1234, 0.5)
>>> (lambda x, y: (int(x), int(x*y) % y/y))(a, 1e15)
(1234, 0.5678)
``````

This also works for me

``````>>> val_int = int(a)
>>> val_fract = a - val_int
``````

This is the way I do it:

``````num = 123.456
split_num = str(num).split('.')
int_part = int(split_num)
decimal_part = int(split_num)
``````

``````In : real = np.array([1234.5678])