Remove all items from a layout

Posted on

Question :

Remove all items from a layout

I was trying to find something that would take a qt layout and delete everything from it. Just to imagine what the window looks like – I have:

QVBoxLayout
     | ------QHboxLayout
                 |---------QWidget
     | ------QHboxLayout
                 |---------QWidget
            .........

So I need something that I can call recursively to CLEAR AND DELETE all the stuff from my parent QVBoxLayout. I tried things mentioned here (Clear all widgets in a layout in pyqt) but none of them work (no correct answer marked anyway). My code looks like this:

def clearLayout(self, layout):
    for i in range(layout.count()):
        if (type(layout.itemAt(i)) == QtGui.QHBoxLayout):
            print "layout " + str(layout.itemAt(i))
            self.clearLayout(layout.itemAt(i))
        else:
            print "widget" + str(layout.itemAt(i))
            layout.itemAt(i).widget().close()

But it gives an error:

               layout.itemAt(i).widget().close()
            AttributeError: 'NoneType' object has no attribute 'close'

=>EDIT
This kinda works (but doesn’t if there is any other Layout than HBoxLayout:

def clearLayout(self, layout):
    layouts = []
    for i in range(layout.count()):
        if (type(layout.itemAt(i)) == QtGui.QHBoxLayout):
            print "layout " + str(layout.itemAt(i))
            self.clearLayout(layout.itemAt(i))
            layouts.append(layout.itemAt(i))
        else:
            print "widget" + str(layout.itemAt(i))
            if (type(layout.itemAt(i)) == QtGui.QWidgetItem):
                layout.itemAt(i).widget().close()
Asked By: kosta5

||

Answer #1:

The safest way to clear a layout is to extract the items with its takeAt method, and then explicitly delete any widgets with deleteLater:

def clearLayout(self, layout):
    if layout is not None:
        while layout.count():
            item = layout.takeAt(0)
            widget = item.widget()
            if widget is not None:
                widget.deleteLater()
            else:
                self.clearLayout(item.layout())
Answered By: ekhumoro

Answer #2:

The problem with your code is QLayout.itemAt() returns a QLayoutItem, QWidgetItem or QSpacerItem depending on the item at that position. So the condition:

type(layout.itemAt(i)) == QtGui.QHBoxLayout

will never be True and you will be trying to do .widget() for a QLayoutItem and that returns None. Thus the error you get. Another thing is, you need to loop backwards. Because removing things from the beginning will shift items and change the order of items.

You need to write your function like this:

def clearLayout(self, layout):
    for i in reversed(range(layout.count())):
        item = layout.itemAt(i)

        if isinstance(item, QtGui.QWidgetItem):
            print "widget" + str(item)
            item.widget().close()
            # or
            # item.widget().setParent(None)
        elif isinstance(item, QtGui.QSpacerItem):
            print "spacer " + str(item)
            # no need to do extra stuff
        else:
            print "layout " + str(item)
            self.clearLayout(item.layout())

        # remove the item from layout
        layout.removeItem(item)    
Answered By: Avaris

Leave a Reply

Your email address will not be published.