Python subprocess readlines() hangs

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Python subprocess readlines() hangs

The task I try to accomplish is to stream a ruby file and print out the output. (NOTE: I don’t want to print out everything at once)

main.py

from subprocess import Popen, PIPE, STDOUT
import pty
import os
file_path = '/Users/luciano/Desktop/ruby_sleep.rb'
command = ' '.join(["ruby", file_path])
master, slave = pty.openpty()
proc = Popen(command, bufsize=0, shell=True, stdout=slave, stderr=slave, close_fds=True)
stdout = os.fdopen(master, 'r', 0)
while proc.poll() is None:
    data = stdout.readline()
    if data != "":
        print(data)
    else:
        break
print("This is never reached!")

ruby_sleep.rb

puts "hello"
sleep 2
puts "goodbye!"

Problem

Streaming the file works fine. The hello/goodbye output is printed with the 2 seconds delay. Exactly as the script should work. The problem is that readline() hangs in the end and never quits. I never reach the last print.

I know there is a lot of questions like this here a stackoverflow but non of them made me solve the problem. I’m not that into the whole subprocess thing so please give me a more hands-on/concrete answer.

Regards

edit

Fix unintended code. (nothing to do with the actual error)

Asked By: vermin

||

Answer #1:

I assume you use pty due to reasons outlined in Q: Why not just use a pipe (popen())? (all other answers so far ignore your “NOTE: I don’t want to print out everything at once”).

pty is Linux only as said in the docs:

Because pseudo-terminal handling is highly platform dependent, there
is code to do it only for Linux. (The Linux code is supposed to work
on other platforms, but hasn’t been tested yet.)

It is unclear how well it works on other OSes.

You could try pexpect:

import sys
import pexpect
pexpect.run("ruby ruby_sleep.rb", logfile=sys.stdout)

Or stdbuf to enable line-buffering in non-interactive mode:

from subprocess import Popen, PIPE, STDOUT
proc = Popen(['stdbuf', '-oL', 'ruby', 'ruby_sleep.rb'],
             bufsize=1, stdout=PIPE, stderr=STDOUT, close_fds=True)
for line in iter(proc.stdout.readline, b''):
    print line,
proc.stdout.close()
proc.wait()

Or using pty from stdlib based on @Antti Haapala’s answer:

#!/usr/bin/env python
import errno
import os
import pty
from subprocess import Popen, STDOUT
master_fd, slave_fd = pty.openpty()  # provide tty to enable
                                     # line-buffering on ruby's side
proc = Popen(['ruby', 'ruby_sleep.rb'],
             stdin=slave_fd, stdout=slave_fd, stderr=STDOUT, close_fds=True)
os.close(slave_fd)
try:
    while 1:
        try:
            data = os.read(master_fd, 512)
        except OSError as e:
            if e.errno != errno.EIO:
                raise
            break # EIO means EOF on some systems
        else:
            if not data: # EOF
                break
            print('got ' + repr(data))
finally:
    os.close(master_fd)
    if proc.poll() is None:
        proc.kill()
    proc.wait()
print("This is reached!")

All three code examples print ‘hello’ immediately (as soon as the first EOL is seen).


leave the old more complicated code example here because it may be referenced and discussed in other posts on SO

Or using pty based on @Antti Haapala’s answer:

import os
import pty
import select
from subprocess import Popen, STDOUT
master_fd, slave_fd = pty.openpty()  # provide tty to enable
                                     # line-buffering on ruby's side
proc = Popen(['ruby', 'ruby_sleep.rb'],
             stdout=slave_fd, stderr=STDOUT, close_fds=True)
timeout = .04 # seconds
while 1:
    ready, _, _ = select.select([master_fd], [], [], timeout)
    if ready:
        data = os.read(master_fd, 512)
        if not data:
            break
        print("got " + repr(data))
    elif proc.poll() is not None: # select timeout
        assert not select.select([master_fd], [], [], 0)[0] # detect race condition
        break # proc exited
os.close(slave_fd) # can't do it sooner: it leads to errno.EIO error
os.close(master_fd)
proc.wait()
print("This is reached!")
Answered By: vermin

Answer #2:

Not sure what is wrong with your code, but the following seems to work for me:

#!/usr/bin/python
from subprocess import Popen, PIPE
import threading
p = Popen('ls', stdout=PIPE)
class ReaderThread(threading.Thread):
    def __init__(self, stream):
        threading.Thread.__init__(self)
        self.stream = stream
    def run(self):
        while True:
            line = self.stream.readline()
            if len(line) == 0:
                break
            print line,
reader = ReaderThread(p.stdout)
reader.start()
# Wait until subprocess is done
p.wait()
# Wait until we've processed all output
reader.join()
print "Done!"

Note that I don’t have Ruby installed and hence cannot check with your actual problem. Works fine with ls, though.

Answered By: jfs

Answer #3:

Basically what you are looking at here is a race condition between your proc.poll() and your readline(). Since the input on the master filehandle is never closed, if the process attempts to do a readline() on it after the ruby process has finished outputting, there will never be anything to read, but the pipe will never close. The code will only work if the shell process closes before your code tries another readline().

Here is the timeline:

readline()
print-output
poll()
readline()
print-output (last line of real output)
poll() (returns false since process is not done)
readline() (waits for more output)
(process is done, but output pipe still open and no poll ever happens for it).

Easy fix is to just use the subprocess module as it suggests in the docs, not in conjunction with openpty:

http://docs.python.org/library/subprocess.html

Here is a very similar problem for further study:

Using subprocess with select and pty hangs when capturing output

Answered By: Florian Brucker

Answer #4:

Try this:

proc = Popen(command, bufsize=0, shell=True, stdout=PIPE, close_fds=True)
for line in proc.stdout:
    print line
print("This is most certainly reached!")

As others have noted, readline() will block when reading data. It will even do so when your child process has died. I am not sure why this does not happen when executing ls as in the other answer, but maybe the ruby interpreter detects that it is writing to a PIPE and therefore it will not close automatically.

Answered By: jmh
The answers/resolutions are collected from stackoverflow, are licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 .

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