Python regular expression again – match url

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Question :

Python regular expression again – match url

I have such regexp:

 re.compile(r"((https?):((//)|(\\))+[wd:#@%/;$()~_?+-=\.&]*)", re.MULTILINE|re.UNICODE)

But that doesn’t include hashbangs (#!). What I need to change, to get it working? I know I can add ! to group with #@% etc, but that will select something like

Check this out: http://example.com/something/!!!

and I want to avoid that.

Asked By: ThomK

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Answer #1:

Don’t try to make your own regular expression for matching URLs, use someone else’s who has already solved such problems, like this one.

Answered By: kindall

Answer #2:

It could be very long but in practice mine works pretty good. Please try this one
((http|https)://)?[a-zA-Z0-9./?:@-_=#]+.([a-zA-Z]){2,6}([a-zA-Z0-9.&/?:@-_=#])*

It matches all of the example below

http://wwww.stackoverflow.com
abc.com
http://test.test-75.1474.stackoverflow.com/
stackoverflow.com/
stackoverflow.com
rfordyce@broadviewnet.com
http://www.example.com/etcetc
www.example.com/etcetc
example.com/etcetc
user:pass@example.com/etcetc
(www.itmag.com)
example.com/etcetc?query=aasd
example.com/etcetc?query=aasd&dest=asds
http://stackoverflow.com/questions/6427530/regular-expression-pattern-to-
match-url-with
www/Christina.V.Scott@gmail.com
line.lundvoll.nilsen@telemed.no.
s.hossain@unsw.edu.au 
s.hossain@unsw.edu.au     
Answered By: Asad

Answer #3:

I’ll admit that I’m a little bit worried about an application that requires a regex like that to match URLs. That said, this seems to work for me:

((https?):((//)|(\\))+([wd:#@%/;$()~_?+-=\.&](#!)?)*)
Answered By: tsm

Answer #4:

This is a common problem, use default libraries.

For python use urlparse

Answered By: estani

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