I have 2 daemons, which should access the same Variable.
I’ve created a 3rd file for global variables and each daemon can access the variable. But when one changes the variable the other one still sees the default value.
time = 0
import datetime import time import glob while(True): glob.time = datetime.datetime.now() time.sleep(30)
import glob while(True): print(glob.time)
it would print 0 everytime
I hope I’ve made my problem clear, and someone can help me.
If you need some more information please feel free to ask.
It looks like (although you don’t tell explicitly that) you are running your programs in a completely independent way: two different invocations of the Python interpreter.
There is no such magic as you are hoping would exist: just as if you have two instances of the same program running, each one will have its instance of variables (global or otherwise).
If you are performing some simple task, the easier way to go is to have one text file as output for each process, and the other process trying to read information from the file generated by each process it wants to know about – (you could even use named pipes in Unixes).
The other way is to have a Python script to coordinate the starting of your daemons using the
multiprocessing stdlib module, and then create a multiprocessing.Manager object to share variables directly between process.
This can be more complicated to set up at first, but it is the clean thing to do. Check the docs on the Manager class here:
The canonical way to share information across modules within a single program is to create a special module (often called config or cfg). Just import the config module in all modules of your application; the module then becomes available as a global name. Because there is only one instance of each module, any changes made to the module object get reflected everywhere.:
import time import glb while(True): glb.t += 1 time.sleep(3) print glb.t
import glb import a while(True): print(glb.t)
t = 0
Output after starting a.py:
python b.py 1 2 3 4 5 6