Question :
I have a textfile, let’s call it goodlines.txt and I want to load it and make a list that contains each line in the text file.
I tried using the split() procedure like this:
>>> f = open('goodlines.txt')
>>> mylist = f.splitlines()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: '_io.TextIOWrapper' object has no attribute 'splitlines'
>>> mylist = f.split()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: '_io.TextIOWrapper' object has no attribute 'split'
Why do I get these errors? Is that not how I use split()? ( I am using python 3.3.2)
Answer #1:
You are using str methods on an open file object.
You can read the file as a list of lines by simply calling list() on the file object:
with open('goodlines.txt') as f:
mylist = list(f)
This does include the newline characters. You can strip those in a list comprehension:
with open('goodlines.txt') as f:
mylist = [line.rstrip('n') for line in f]
Answer #2:
Try this:
>>> f = open('goodlines.txt')
>>> mylist = f.readlines()
open() function returns a file object. And for file object, there is no method like splitlines() or split(). You could use dir(f) to see all the methods of file object.
Answer #3:
You’re not reading the file content:
my_file_contents = f.read()
See the docs for further infos
You could, without calling read() or readlines() loop over your file object:
f = open('goodlines.txt')
for line in f:
print(line)
If you want a list out of it (without n as you asked)
my_list = [line.rstrip('n') for line in f]
