Question :
python 2.7 equivalent of built-in method int.from_bytes
I’m trying to make my project python2.7 and 3 compatible and python 3 has the built in method int.from_bytes. Does the equivalent exist in python 2.7 or rather what would be the best way to make this code 2.7 and 3 compatible?
>>> int.from_bytes(b"f483", byteorder="big")
1714698291
Answer #1:
You can treat it as an encoding (Python 2 specific):
>>> int('f483'.encode('hex'), 16)
1714698291
Or in Python 2 and Python 3:
>>> int(codecs.encode(b'f483', 'hex'), 16)
1714698291
The advantage is the string is not limited to a specific size assumption. The disadvantage is it is unsigned.
Answer #2:
struct.unpack(">i","f483")[0]
maybe?
> means big-endian and i means signed 32 bit int
Answer #3:
Use the struct module to unpack your bytes into integers.
import struct
>>> struct.unpack("<L", "yxccxa6xbb")[0]
3148270713L
Answer #4:
> import binascii
> barray = bytearray([0xAB, 0xCD, 0xEF])
> n = int(binascii.hexlify(barray), 16)
> print("0x%02X" % n)
0xABCDEF
