Print list without brackets in a single row

Answer #1:

print(', '.join(names))

This, like it sounds, just takes all the elements of the list and joins them with ', '.

Answer #2:

Here is a simple one.

names = ["Sam", "Peter", "James", "Julian", "Ann"]
print(*names, sep=", ")

the star unpacks the list and return every element in the list.

Answer #3:

General solution, works on arrays of non-strings:

>>> print str(names)[1:-1]
'Sam', 'Peter', 'James', 'Julian', 'Ann'

Answer #4:

If the input array is Integer type then you need to first convert array into string type array and then use join method for joining with , or space whatever you want. e.g:

>>> arr = [1, 2, 4, 3]
>>> print(", " . join(arr))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: sequence item 0: expected string, int found
>>> sarr = [str(a) for a in arr]
>>> print(", " . join(sarr))
1, 2, 4, 3
>>>

Direct using of join which will join the integer and string will throw error as show above.

Answer #5:

There are two answers , First is use ‘sep’ setting

>>> print(*names, sep = ', ')

The other is below

>>> print(', '.join(names))

Answer #6:

This is what you need

", ".join(names)

Answer #7:

','.join(list) will work only if all the items in the list are strings. If you are looking to convert a list of numbers to a comma separated string. such as a = [1, 2, 3, 4] into '1,2,3,4' then you can either

str(a)[1:-1] # '1, 2, 3, 4'

or

str(a).lstrip('[').rstrip(']') # '1, 2, 3, 4'

although this won’t remove any nested list.

To convert it back to a list

a = '1,2,3,4'
import ast
ast.literal_eval('['+a+']')
#[1, 2, 3, 4]

Answer #8:

You need to loop through the list and use end=" "to keep it on one line

names = ["Sam", "Peter", "James", "Julian", "Ann"]
    index=0
    for name in names:
        print(names[index], end=", ")
        index += 1