n-grams in python, four, five, six grams?

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Question :

n-grams in python, four, five, six grams?

I’m looking for a way to split a text into n-grams.
Normally I would do something like:

import nltk
from nltk import bigrams
string = "I really like python, it's pretty awesome."
string_bigrams = bigrams(string)
print string_bigrams

I am aware that nltk only offers bigrams and trigrams, but is there a way to split my text in four-grams, five-grams or even hundred-grams?

Thanks!

Asked By: Shifu

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Answer #1:

Great native python based answers given by other users. But here’s the nltk approach (just in case, the OP gets penalized for reinventing what’s already existing in the nltk library).

There is an ngram module that people seldom use in nltk. It’s not because it’s hard to read ngrams, but training a model base on ngrams where n > 3 will result in much data sparsity.

from nltk import ngrams

sentence = 'this is a foo bar sentences and i want to ngramize it'

n = 6
sixgrams = ngrams(sentence.split(), n)

for grams in sixgrams:
  print grams
Answered By: alvas

Answer #2:

I’m surprised that this hasn’t shown up yet:

In [34]: sentence = "I really like python, it's pretty awesome.".split()

In [35]: N = 4

In [36]: grams = [sentence[i:i+N] for i in xrange(len(sentence)-N+1)]

In [37]: for gram in grams: print gram
['I', 'really', 'like', 'python,']
['really', 'like', 'python,', "it's"]
['like', 'python,', "it's", 'pretty']
['python,', "it's", 'pretty', 'awesome.']
Answered By: inspectorG4dget

Answer #3:

Using only nltk tools

from nltk.tokenize import word_tokenize
from nltk.util import ngrams

def get_ngrams(text, n ):
    n_grams = ngrams(word_tokenize(text), n)
    return [ ' '.join(grams) for grams in n_grams]

Example output

get_ngrams('This is the simplest text i could think of', 3 )

['This is the', 'is the simplest', 'the simplest text', 'simplest text i', 'text i could', 'i could think', 'could think of']

In order to keep the ngrams in array format just remove ' '.join

Answered By: ???????? ??????

Answer #4:

here is another simple way for do n-grams

>>> from nltk.util import ngrams
>>> text = "I am aware that nltk only offers bigrams and trigrams, but is there a way to split my text in four-grams, five-grams or even hundred-grams"
>>> tokenize = nltk.word_tokenize(text)
>>> tokenize
['I', 'am', 'aware', 'that', 'nltk', 'only', 'offers', 'bigrams', 'and', 'trigrams', ',', 'but', 'is', 'there', 'a', 'way', 'to', 'split', 'my', 'text', 'in', 'four-grams', ',', 'five-grams', 'or', 'even', 'hundred-grams']
>>> bigrams = ngrams(tokenize,2)
>>> bigrams
[('I', 'am'), ('am', 'aware'), ('aware', 'that'), ('that', 'nltk'), ('nltk', 'only'), ('only', 'offers'), ('offers', 'bigrams'), ('bigrams', 'and'), ('and', 'trigrams'), ('trigrams', ','), (',', 'but'), ('but', 'is'), ('is', 'there'), ('there', 'a'), ('a', 'way'), ('way', 'to'), ('to', 'split'), ('split', 'my'), ('my', 'text'), ('text', 'in'), ('in', 'four-grams'), ('four-grams', ','), (',', 'five-grams'), ('five-grams', 'or'), ('or', 'even'), ('even', 'hundred-grams')]
>>> trigrams=ngrams(tokenize,3)
>>> trigrams
[('I', 'am', 'aware'), ('am', 'aware', 'that'), ('aware', 'that', 'nltk'), ('that', 'nltk', 'only'), ('nltk', 'only', 'offers'), ('only', 'offers', 'bigrams'), ('offers', 'bigrams', 'and'), ('bigrams', 'and', 'trigrams'), ('and', 'trigrams', ','), ('trigrams', ',', 'but'), (',', 'but', 'is'), ('but', 'is', 'there'), ('is', 'there', 'a'), ('there', 'a', 'way'), ('a', 'way', 'to'), ('way', 'to', 'split'), ('to', 'split', 'my'), ('split', 'my', 'text'), ('my', 'text', 'in'), ('text', 'in', 'four-grams'), ('in', 'four-grams', ','), ('four-grams', ',', 'five-grams'), (',', 'five-grams', 'or'), ('five-grams', 'or', 'even'), ('or', 'even', 'hundred-grams')]
>>> fourgrams=ngrams(tokenize,4)
>>> fourgrams
[('I', 'am', 'aware', 'that'), ('am', 'aware', 'that', 'nltk'), ('aware', 'that', 'nltk', 'only'), ('that', 'nltk', 'only', 'offers'), ('nltk', 'only', 'offers', 'bigrams'), ('only', 'offers', 'bigrams', 'and'), ('offers', 'bigrams', 'and', 'trigrams'), ('bigrams', 'and', 'trigrams', ','), ('and', 'trigrams', ',', 'but'), ('trigrams', ',', 'but', 'is'), (',', 'but', 'is', 'there'), ('but', 'is', 'there', 'a'), ('is', 'there', 'a', 'way'), ('there', 'a', 'way', 'to'), ('a', 'way', 'to', 'split'), ('way', 'to', 'split', 'my'), ('to', 'split', 'my', 'text'), ('split', 'my', 'text', 'in'), ('my', 'text', 'in', 'four-grams'), ('text', 'in', 'four-grams', ','), ('in', 'four-grams', ',', 'five-grams'), ('four-grams', ',', 'five-grams', 'or'), (',', 'five-grams', 'or', 'even'), ('five-grams', 'or', 'even', 'hundred-grams')]
Answered By: M.A.Hassan

Answer #5:

People have already answered pretty nicely for the scenario where you need bigrams or trigrams but if you need everygram for the sentence in that case you can use nltk.util.everygrams

>>> from nltk.util import everygrams

>>> message = "who let the dogs out"

>>> msg_split = message.split()

>>> list(everygrams(msg_split))
[('who',), ('let',), ('the',), ('dogs',), ('out',), ('who', 'let'), ('let', 'the'), ('the', 'dogs'), ('dogs', 'out'), ('who', 'let', 'the'), ('let', 'the', 'dogs'), ('the', 'dogs', 'out'), ('who', 'let', 'the', 'dogs'), ('let', 'the', 'dogs', 'out'), ('who', 'let', 'the', 'dogs', 'out')]

Incase you have a limit like in case of trigrams where the max length should be 3 then you can use max_len param to specify it.

>>> list(everygrams(msg_split, max_len=2))
[('who',), ('let',), ('the',), ('dogs',), ('out',), ('who', 'let'), ('let', 'the'), ('the', 'dogs'), ('dogs', 'out')]

You can just modify the max_len param to achieve whatever gram i.e four gram, five gram, six or even hundred gram.

The previous mentioned solutions can be modified to implement the above mentioned solution but this solution is much straight forward than that.

For further reading click here

And when you just need a specific gram like bigram or trigram etc you can use the nltk.util.ngrams as mentioned in M.A.Hassan’s answer.

Answered By: im_bhatman

Answer #6:

You can easily whip up your own function to do this using itertools:

from itertools import izip, islice, tee
s = 'spam and eggs'
N = 3
trigrams = izip(*(islice(seq, index, None) for index, seq in enumerate(tee(s, N))))
list(trigrams)
# [('s', 'p', 'a'), ('p', 'a', 'm'), ('a', 'm', ' '),
# ('m', ' ', 'a'), (' ', 'a', 'n'), ('a', 'n', 'd'),
# ('n', 'd', ' '), ('d', ' ', 'e'), (' ', 'e', 'g'),
# ('e', 'g', 'g'), ('g', 'g', 's')]
Answered By: tzaman

Answer #7:

A more elegant approach to build bigrams with python’s builtin zip().
Simply convert the original string into a list by split(), then pass the list once normally and once offset by one element.

string = "I really like python, it's pretty awesome."

def find_bigrams(s):
    input_list = s.split(" ")
    return zip(input_list, input_list[1:])

def find_ngrams(s, n):
  input_list = s.split(" ")
  return zip(*[input_list[i:] for i in range(n)])

find_bigrams(string)

[('I', 'really'), ('really', 'like'), ('like', 'python,'), ('python,', "it's"), ("it's", 'pretty'), ('pretty', 'awesome.')]
Answered By: Serendipity

Answer #8:

I have never dealt with nltk but did N-grams as part of some small class project. If you want to find the frequency of all N-grams occurring in the string, here is a way to do that. D would give you the histogram of your N-words.

D = dict()
string = 'whatever string...'
strparts = string.split()
for i in range(len(strparts)-N): # N-grams
    try:
        D[tuple(strparts[i:i+N])] += 1
    except:
        D[tuple(strparts[i:i+N])] = 1
Answered By: Nik

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