Max retries exceeded with URL in requests

Posted on

Question :

Max retries exceeded with URL in requests

I’m trying to get the content of App Store > Business:

import requests
from lxml import html

page = requests.get("https://itunes.apple.com/in/genre/ios-business/id6000?mt=8")
tree = html.fromstring(page.text)

flist = []
plist = []
for i in range(0, 100):
    app = tree.xpath("//div[@class='column first']/ul/li/a/@href")
    ap = app[0]
    page1 = requests.get(ap)

When I try the range with (0,2) it works, but when I put the range in 100s it shows this error:

Traceback (most recent call last):
  File "/home/preetham/Desktop/eg.py", line 17, in <module>
    page1 = requests.get(ap)
  File "/usr/local/lib/python2.7/dist-packages/requests/api.py", line 55, in get
    return request('get', url, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/requests/api.py", line 44, in request
    return session.request(method=method, url=url, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/requests/sessions.py", line 383, in request
    resp = self.send(prep, **send_kwargs)
  File "/usr/local/lib/python2.7/dist-packages/requests/sessions.py", line 486, in send
    r = adapter.send(request, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/requests/adapters.py", line 378, in send
    raise ConnectionError(e)
requests.exceptions.ConnectionError: HTTPSConnectionPool(host='itunes.apple.com', port=443): Max retries exceeded with url: /in/app/adobe-reader/id469337564?mt=8 (Caused by <class 'socket.gaierror'>: [Errno -2] Name or service not known)

Answer #1:

What happened here is that itunes server refuses your connection (you’re sending too many requests from same ip address in short period of time)

Max retries exceeded with url: /in/app/adobe-reader/id469337564?mt=8

error trace is misleading it should be something like “No connection could be made because the target machine actively refused it”.

There is an issue at about python.requests lib at Github, check it out here

To overcome this issue (not so much an issue as it is misleading debug trace) you should catch connection related exceptions like so:

try:
    page1 = requests.get(ap)
except requests.exceptions.ConnectionError:
    r.status_code = "Connection refused"

Another way to overcome this problem is if you use enough time gap to send requests to server this can be achieved by sleep(timeinsec) function in python (don’t forget to import sleep)

from time import sleep

All in all requests is awesome python lib, hope that solves your problem.

Answered By: djra

Answer #2:

Just use requests' features:

import requests
from requests.adapters import HTTPAdapter
from requests.packages.urllib3.util.retry import Retry


session = requests.Session()
retry = Retry(connect=3, backoff_factor=0.5)
adapter = HTTPAdapter(max_retries=retry)
session.mount('http://', adapter)
session.mount('https://', adapter)

session.get(url)

This will GET the URL and retry 3 times in case of requests.exceptions.ConnectionError. backoff_factor will help to apply delays between attempts to avoid to fail again in case of periodic request quota.

Take a look at requests.packages.urllib3.util.retry.Retry, it has many options to simplify retries.

Answered By: Zulu

Answer #3:

Just do this,

Paste the following code in place of page = requests.get(url):

import time

page = ''
while page == '':
    try:
        page = requests.get(url)
        break
    except:
        print("Connection refused by the server..")
        print("Let me sleep for 5 seconds")
        print("ZZzzzz...")
        time.sleep(5)
        print("Was a nice sleep, now let me continue...")
        continue

You’re welcome 🙂

Answered By: jatin

Answer #4:

pip install pyopenssl seemed to solve it for me.

https://github.com/requests/requests/issues/4246

Answered By: Akshar

Answer #5:

I got similar problem but the following code worked for me.

url = <some REST url>    
page = requests.get(url, verify=False)

“verify=False” disables SSL verification. Try and catch can be added as usual.

Answered By: Raj Stha

Answer #6:

It is always good to implement exception handling. It does not only help to avoid unexpected exit of script but can also help to log errors and info notification. When using Python requests I prefer to catch exceptions like this:

    try:
        res = requests.get(adress,timeout=30)
    except requests.ConnectionError as e:
        print("OOPS!! Connection Error. Make sure you are connected to Internet. Technical Details given below.n")
        print(str(e))            
        renewIPadress()
        continue
    except requests.Timeout as e:
        print("OOPS!! Timeout Error")
        print(str(e))
        renewIPadress()
        continue
    except requests.RequestException as e:
        print("OOPS!! General Error")
        print(str(e))
        renewIPadress()
        continue
    except KeyboardInterrupt:
        print("Someone closed the program")

Here renewIPadress() is a user define function which can change the IP address if it get blocked. You can go without this function.

Answered By: Tanmoy Datta

Answer #7:

Specifying the proxy in a corporate environment solved it for me.

page = requests.get("http://www.google.com:80", proxies={"http": "http://111.233.225.166:1234"})

The full error is:

requests.exceptions.ConnectionError: HTTPSConnectionPool(host=’www.google.com’, port=80): Max retries exceeded with url: / (Caused by NewConnectionError(‘: Failed to establish a new connection: [WinError 10060] A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond’))

Answered By: Jeremy Thompson

Answer #8:

Adding my own experience for those who are experiencing this in the future. My specific error was

Failed to establish a new connection: [Errno 8] nodename nor servname provided, or not known'

It turns out that this was actually because I had reach the maximum number of open files on my system. It had nothing to do with failed connections, or even a DNS error as indicated.

Answered By: Oded

Leave a Reply

Your email address will not be published.