In Python, how do I read the exif data for an image?

Posted on

Question :

In Python, how do I read the exif data for an image?

I’m using PIL. How do I turn the EXIF data of a picture into a dictionary?

Asked By: TIMEX


Answer #1:

You can use the _getexif() protected method of a PIL Image.

import PIL.Image
img ='img.jpg')
exif_data = img._getexif()

This should give you a dictionary indexed by EXIF numeric tags. If you want the dictionary indexed by the actual EXIF tag name strings, try something like:

import PIL.ExifTags
exif = {
    PIL.ExifTags.TAGS[k]: v
    for k, v in img._getexif().items()
    if k in PIL.ExifTags.TAGS
Answered By: payne

Answer #2:

You can also use the ExifRead module:

import exifread
# Open image file for reading (binary mode)
f = open(path_name, 'rb')

# Return Exif tags
tags = exifread.process_file(f)
Answered By: ianaré

Answer #3:

For Python3.x and starting Pillow==6.0.0, Image objects now provide a getexif() method that returns <class 'PIL.Image.Exif'> or None if the image has no EXIF data.

From Pillow 6.0.0 release notes:

getexif() has been added, which returns an Exif instance. Values can
be retrieved and set like a dictionary. When saving JPEG, PNG or WEBP,
the instance can be passed as an exif argument to include any changes
in the output image.

As stated, the Exif output can simply be casted to a dict with the EXIF data accessible as regular key-value pairs. The keys are 16-bit integers that can be mapped to their string names using the ExifTags.TAGS module.

from PIL import Image, ExifTags

img ="sample.jpg")
img_exif = img.getexif()
# <class 'PIL.Image.Exif'>

if img_exif is None:
    print("Sorry, image has no exif data.")
    img_exif_dict = dict(img_exif)
    # { ... 42035: 'FUJIFILM', 42036: 'XF23mmF2 R WR', 42037: '75A14188' ... }
    for key, val in img_exif_dict.items():
        if key in ExifTags.TAGS:
            # ExifVersion:b'0230'
            # ...
            # FocalLength:(2300, 100)
            # ColorSpace:1
            # FocalLengthIn35mmFilm:35
            # ...
            # Model:'X-T2'
            # Make:'FUJIFILM'
            # ...
            # DateTime:'2019:12:01 21:30:07'
            # ...

Tested with Python 3.6.8 and Pillow==6.0.0.

Answered By: Gino Mempin

Answer #4:

I use this:

import os,sys
from PIL import Image
from PIL.ExifTags import TAGS

for (k,v) in[1])._getexif().items():
        print('%s = %s' % (TAGS.get(k), v))

or to get a specific field:

def get_field (exif,field) :
  for (k,v) in exif.items():
     if TAGS.get(k) == field:
        return v

exif = image._getexif()
print get_field(exif,'ExposureTime')
Answered By: Mike Redrobe

Answer #5:

import sys
import PIL
import PIL.Image as PILimage
from PIL import ImageDraw, ImageFont, ImageEnhance
from PIL.ExifTags import TAGS, GPSTAGS

class Worker(object):
    def __init__(self, img):
        self.img = img
        self.exif_data = self.get_exif_data() = self.get_lat()
        self.lon = self.get_lon() =self.get_date_time()
        super(Worker, self).__init__()

    def get_if_exist(data, key):
        if key in data:
            return data[key]
        return None

    def convert_to_degress(value):
        """Helper function to convert the GPS coordinates
        stored in the EXIF to degress in float format"""
        d0 = value[0][0]
        d1 = value[0][1]
        d = float(d0) / float(d1)
        m0 = value[1][0]
        m1 = value[1][1]
        m = float(m0) / float(m1)

        s0 = value[2][0]
        s1 = value[2][1]
        s = float(s0) / float(s1)

        return d + (m / 60.0) + (s / 3600.0)

    def get_exif_data(self):
        """Returns a dictionary from the exif data of an PIL Image item. Also
        converts the GPS Tags"""
        exif_data = {}
        info = self.img._getexif()
        if info:
            for tag, value in info.items():
                decoded = TAGS.get(tag, tag)
                if decoded == "GPSInfo":
                    gps_data = {}
                    for t in value:
                        sub_decoded = GPSTAGS.get(t, t)
                        gps_data[sub_decoded] = value[t]

                    exif_data[decoded] = gps_data
                    exif_data[decoded] = value
        return exif_data

    def get_lat(self):
        """Returns the latitude and longitude, if available, from the 
        provided exif_data (obtained through get_exif_data above)"""
        # print(exif_data)
        if 'GPSInfo' in self.exif_data:
            gps_info = self.exif_data["GPSInfo"]
            gps_latitude = self.get_if_exist(gps_info, "GPSLatitude")
            gps_latitude_ref = self.get_if_exist(gps_info, 'GPSLatitudeRef')
            if gps_latitude and gps_latitude_ref:
                lat = self.convert_to_degress(gps_latitude)
                if gps_latitude_ref != "N":
                    lat = 0 - lat
                lat = str(f"{lat:.{5}f}")
                return lat
            return None

    def get_lon(self):
        """Returns the latitude and longitude, if available, from the 
        provided exif_data (obtained through get_exif_data above)"""
        # print(exif_data)
        if 'GPSInfo' in self.exif_data:
            gps_info = self.exif_data["GPSInfo"]
            gps_longitude = self.get_if_exist(gps_info, 'GPSLongitude')
            gps_longitude_ref = self.get_if_exist(gps_info, 'GPSLongitudeRef')
            if gps_longitude and gps_longitude_ref:
                lon = self.convert_to_degress(gps_longitude)
                if gps_longitude_ref != "E":
                    lon = 0 - lon
                lon = str(f"{lon:.{5}f}")
                return lon
            return None

    def get_date_time(self):
        if 'DateTime' in self.exif_data:
            date_and_time = self.exif_data['DateTime']
            return date_and_time 

if __name__ == '__main__':
        img =[1])
        image = Worker(img)
        lat =
        lon = image.lon
        date =
        print(date, lat, lon)

    except Exception as e:
Answered By: Kirill Vladi

Answer #6:

I have found that using ._getexif doesn’t work in higher python versions, moreover, it is a protected class and one should avoid using it if possible.
After digging around the debugger this is what I found to be the best way to get the EXIF data for an image:

from PIL import Image

def get_exif(path):

This returns a dictionary of all the EXIF data of an image.

Note: For Python3.x use Pillow instead of PIL

Answered By: Param Kapur

Answer #7:

Here’s the one that may be little easier to read. Hope this is helpful.

from PIL import Image
from PIL import ExifTags

exifData = {}
img =
exifDataRaw = img._getexif()
for tag, value in exifDataRaw.items():
    decodedTag = ExifTags.TAGS.get(tag, tag)
    exifData[decodedTag] = value
Answered By: Raj Stha

Answer #8:

I usually use pyexiv2 to set exif information in JPG files, but when I import the library in a script QGIS script crash.

I found a solution using the library exif:

It’s so easy to use, and with Qgis I don,’t have any problem.

In this code I insert GPS coordinates to a snapshot of screen:

from exif import Image
with open(file_name, 'rb') as image_file:
    my_image = Image(image_file)

my_image.make = "Python"
my_image.gps_longitude_ref= exif_lon_ref
my_image.gps_longitude= exif_lon

with open(file_name, 'wb') as new_image_file:
Answered By: RBenet

Leave a Reply

Your email address will not be published.