How to send email attachments?

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How to send email attachments?

I am having problems understanding how to email an attachment using Python. I have successfully emailed simple messages with the smtplib. Could someone please explain how to send an attachment in an email. I know there are other posts online but as a Python beginner I find them hard to understand.

Asked By: Richard

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Answer #1:

Here’s another:

import smtplib
from os.path import basename
from email.mime.application import MIMEApplication
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
def send_mail(send_from, send_to, subject, text, files=None,
              server="127.0.0.1"):
    assert isinstance(send_to, list)
    msg = MIMEMultipart()
    msg['From'] = send_from
    msg['To'] = COMMASPACE.join(send_to)
    msg['Date'] = formatdate(localtime=True)
    msg['Subject'] = subject
    msg.attach(MIMEText(text))
    for f in files or []:
        with open(f, "rb") as fil:
            part = MIMEApplication(
                fil.read(),
                Name=basename(f)
            )
        # After the file is closed
        part['Content-Disposition'] = 'attachment; filename="%s"' % basename(f)
        msg.attach(part)
    smtp = smtplib.SMTP(server)
    smtp.sendmail(send_from, send_to, msg.as_string())
    smtp.close()

It’s much the same as the first example… But it should be easier to drop in.

Answered By: Oli

Answer #2:

Here is the modified version from Oli for python 3

import smtplib
from pathlib import Path
from email.mime.multipart import MIMEMultipart
from email.mime.base import MIMEBase
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
from email import encoders
def send_mail(send_from, send_to, subject, message, files=[],
              server="localhost", port=587, username='', password='',
              use_tls=True):
    """Compose and send email with provided info and attachments.
    Args:
        send_from (str): from name
        send_to (list[str]): to name(s)
        subject (str): message title
        message (str): message body
        files (list[str]): list of file paths to be attached to email
        server (str): mail server host name
        port (int): port number
        username (str): server auth username
        password (str): server auth password
        use_tls (bool): use TLS mode
    """
    msg = MIMEMultipart()
    msg['From'] = send_from
    msg['To'] = COMMASPACE.join(send_to)
    msg['Date'] = formatdate(localtime=True)
    msg['Subject'] = subject
    msg.attach(MIMEText(message))
    for path in files:
        part = MIMEBase('application', "octet-stream")
        with open(path, 'rb') as file:
            part.set_payload(file.read())
        encoders.encode_base64(part)
        part.add_header('Content-Disposition',
                        'attachment; filename="{}"'.format(Path(path).name))
        msg.attach(part)
    smtp = smtplib.SMTP(server, port)
    if use_tls:
        smtp.starttls()
    smtp.login(username, password)
    smtp.sendmail(send_from, send_to, msg.as_string())
    smtp.quit()
Answered By: Ehsan Iran-Nejad

Answer #3:

This is the code I ended up using:

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email import Encoders
SUBJECT = "Email Data"
msg = MIMEMultipart()
msg['Subject'] = SUBJECT
msg['From'] = self.EMAIL_FROM
msg['To'] = ', '.join(self.EMAIL_TO)
part = MIMEBase('application', "octet-stream")
part.set_payload(open("text.txt", "rb").read())
Encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="text.txt"')
msg.attach(part)
server = smtplib.SMTP(self.EMAIL_SERVER)
server.sendmail(self.EMAIL_FROM, self.EMAIL_TO, msg.as_string())

Code is much the same as Oli’s post.

Code based from Binary file email attachment problem post.

Answered By: Richard

Answer #4:

from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
from email.MIMEImage import MIMEImage
import smtplib
msg = MIMEMultipart()
msg.attach(MIMEText(file("text.txt").read()))
msg.attach(MIMEImage(file("image.png").read()))
# to send
mailer = smtplib.SMTP()
mailer.connect()
mailer.sendmail(from_, to, msg.as_string())
mailer.close()

Adapted from here.

Answered By: Oli

Answer #5:

Another way with python 3 (If someone is searching):

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
fromaddr = "sender mail address"
toaddr = "receiver mail address"
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = toaddr
msg['Subject'] = "SUBJECT OF THE EMAIL"
body = "TEXT YOU WANT TO SEND"
msg.attach(MIMEText(body, 'plain'))
filename = "fileName"
attachment = open("path of file", "rb")
part = MIMEBase('application', 'octet-stream')
part.set_payload((attachment).read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= %s" % filename)
msg.attach(part)
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
server.login(fromaddr, "sender mail password")
text = msg.as_string()
server.sendmail(fromaddr, toaddr, text)
server.quit()

Make sure to allow “less secure apps” on your Gmail account

Answered By: Sudarshan

Answer #6:

Gmail version, working with Python 3.6 (note that you will need to change your Gmail settings to be able to send email via smtp from it:

import smtplib
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.application import MIMEApplication
from os.path import basename
def send_mail(send_from: str, subject: str, text: str,
send_to: list, files= None):
    send_to= default_address if not send_to else send_to
    msg = MIMEMultipart()
    msg['From'] = send_from
    msg['To'] = ', '.join(send_to)
    msg['Subject'] = subject
    msg.attach(MIMEText(text))
    for f in files or []:
        with open(f, "rb") as fil:
            ext = f.split('.')[-1:]
            attachedfile = MIMEApplication(fil.read(), _subtype = ext)
            attachedfile.add_header(
                'content-disposition', 'attachment', filename=basename(f) )
        msg.attach(attachedfile)
    smtp = smtplib.SMTP(host="smtp.gmail.com", port= 587)
    smtp.starttls()
    smtp.login(username,password)
    smtp.sendmail(send_from, send_to, msg.as_string())
    smtp.close()

Usage:

username = 'my-address@gmail.com'
password = 'top-secret'
default_address = ['my-address2@gmail.com']
send_mail(send_from= username,
subject="test",
text="text",
send_to= None,
files= # pass a list with the full filepaths here...
)

To use with any other email provider, just change the smtp configurations.

Answered By: Ferrarezi

Answer #7:

The simplest code I could get to is:

#for attachment email
from django.core.mail import EmailMessage
    def attachment_email(request):
            email = EmailMessage(
            'Hello', #subject
            'Body goes here', #body
            'MyEmail@MyEmail.com', #from
            ['SendTo@SendTo.com'], #to
            ['bcc@example.com'], #bcc
            reply_to=['other@example.com'],
            headers={'Message-ID': 'foo'},
            )
            email.attach_file('/my/path/file')
            email.send()

It was based on the official Django documentation

Answered By: Andrade

Answer #8:

Other answers are excellent, though I still wanted to share a different approach in case someone is looking for alternatives.

Main difference here is that using this approach you can use HTML/CSS to format your message, so you can get creative and give some styling to your email. Though you aren’t enforced to use HTML, you can also still use only plain text.

Notice that this function accepts sending the email to multiple recipients and also allows to attach multiple files.

I’ve only tried this on Python 2, but I think it should work fine on 3 as well:

import os.path
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.application import MIMEApplication
def send_email(subject, message, from_email, to_email=[], attachment=[]):
    """
    :param subject: email subject
    :param message: Body content of the email (string), can be HTML/CSS or plain text
    :param from_email: Email address from where the email is sent
    :param to_email: List of email recipients, example: ["a@a.com", "b@b.com"]
    :param attachment: List of attachments, exmaple: ["file1.txt", "file2.txt"]
    """
    msg = MIMEMultipart()
    msg['Subject'] = subject
    msg['From'] = from_email
    msg['To'] = ", ".join(to_email)
    msg.attach(MIMEText(message, 'html'))
    for f in attachment:
        with open(f, 'rb') as a_file:
            basename = os.path.basename(f)
            part = MIMEApplication(a_file.read(), Name=basename)
        part['Content-Disposition'] = 'attachment; filename="%s"' % basename
        msg.attach(part)
    email = smtplib.SMTP('your-smtp-host-name.com')
    email.sendmail(from_email, to_email, msg.as_string())

I hope this helps! 🙂

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