How to remove all characters after a specific character in python?

Answer #1:

Split on your separator at most once, and take the first piece:

sep = '...'
stripped = text.split(sep, 1)[0]

You didn’t say what should happen if the separator isn’t present. Both this and Alex’s solution will return the entire string in that case.

Answer #2:

Assuming your separator is ‘…’, but it can be any string.

text = 'some string... this part will be removed.'
head, sep, tail = text.partition('...')

>>> print head
some string

If the separator is not found, head will contain all of the original string.

The partition function was added in Python 2.5.

partition(…)
S.partition(sep) -> (head, sep, tail)

Searches for the separator sep in S, and returns the part before it,
the separator itself, and the part after it.  If the separator is not
found, returns S and two empty strings.

Answer #3:

If you want to remove everything after the last occurrence of separator in a string I find this works well:

<separator>.join(string_to_split.split(<separator>)[:-1])

For example, if string_to_split is a path like root/location/child/too_far.exe and you only want the folder path, you can split by "/".join(string_to_split.split("/")[:-1]) and you’ll get
root/location/child

Answer #4:

Without a RE (which I assume is what you want):

def remafterellipsis(text):
  where_ellipsis = text.find('...')
  if where_ellipsis == -1:
    return text
  return text[:where_ellipsis + 3]

or, with a RE:

import re

def remwithre(text, there=re.compile(re.escape('...')+'.*')):
  return there.sub('', text)

Answer #5:

import re
test = "This is a test...we should not be able to see this"
res = re.sub(r'....*',"",test)
print(res)

Output: “This is a test”

Answer #6:

From a file:

import re
sep = '...'

with open("requirements.txt") as file_in:
    lines = []
    for line in file_in:
        res = line.split(sep, 1)[0]
        print(res)

Answer #7:

The method find will return the character position in a string. Then, if you want remove every thing from the character, do this:

mystring = "123?567"
mystring[ 0 : mystring.index("?")]

>> '123'

If you want to keep the character, add 1 to the character position.

Answer #8:

another easy way using re will be

import re, clr

text = 'some string... this part will be removed.'

text= re.search(r'(A.*)....+',url,re.DOTALL|re.IGNORECASE).group(1)

// text = some string