How to get week number in Python?

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Question :

How to get week number in Python?

How to find out what week number is current year on June 16th (wk24) with Python?

Asked By: Gerry

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Answer #1:

datetime.date has a isocalendar() method, which returns a tuple containing the calendar week:

>>> import datetime
>>> datetime.date(2010, 6, 16).isocalendar()[1]
24

datetime.date.isocalendar() is an instance-method returning a tuple containing year, weeknumber and weekday in respective order for the given date instance.

Answered By: Horst Gutmann

Answer #2:

You can get the week number directly from datetime as string.

>>> import datetime
>>> datetime.date(2010, 6, 16).strftime("%V")
'24'

Also you can get different “types” of the week number of the year changing the strftime parameter for:

%UWeek number of the year (Sunday as the first day of the week) as a zero padded decimal number. All days in a new year preceding the first Sunday are considered to be in week 0. Examples: 00, 01, …, 53

%W – Week number of the year (Monday as the first day of the week) as a decimal number. All days in a new year preceding the first Monday are considered to be in week 0. Examples: 00, 01, …, 53

[…]

(Added in Python 3.6, backported to some distribution’s Python 2.7’s) Several additional directives not required by the C89 standard are included for convenience. These parameters all correspond to ISO 8601 date values. These may not be available on all platforms when used with the strftime() method.

[…]

%VISO 8601 week as a decimal number with Monday as the first day of the week. Week 01 is the week containing Jan 4. Examples: 01, 02, …, 53

from: datetime — Basic date and time types — Python 3.7.3 documentation

I’ve found out about it from here. It worked for me in Python 2.7.6

Answered By: jotacor

Answer #3:

I believe date.isocalendar() is going to be the answer. This article explains the math behind ISO 8601 Calendar. Check out the date.isocalendar() portion of the datetime page of the Python documentation.

>>> dt = datetime.date(2010, 6, 16) 
>>> wk = dt.isocalendar()[1]
24

.isocalendar() return a 3-tuple with (year, wk num, wk day). dt.isocalendar()[0] returns the year,dt.isocalendar()[1] returns the week number, dt.isocalendar()[2] returns the week day. Simple as can be.

Answered By: Byron Sommardahl

Answer #4:

Here’s another option:

import time
from time import gmtime, strftime
d = time.strptime("16 Jun 2010", "%d %b %Y")
print(strftime(d, '%U'))

which prints 24.

See: http://docs.python.org/library/datetime.html#strftime-and-strptime-behavior

Answered By: Bart Kiers

Answer #5:

The ISO week suggested by others is a good one, but it might not fit your needs. It assumes each week begins with a Monday, which leads to some interesting anomalies at the beginning and end of the year.

If you’d rather use a definition that says week 1 is always January 1 through January 7, regardless of the day of the week, use a derivation like this:

>>> testdate=datetime.datetime(2010,6,16)
>>> print(((testdate - datetime.datetime(testdate.year,1,1)).days // 7) + 1)
24
Answered By: Mark Ransom

Answer #6:

Generally to get the current week number (starts from Sunday):

from datetime import *
today = datetime.today()
print today.strftime("%U")
Answered By: Chaggster

Answer #7:

There are many systems for week numbering. The following are the most common systems simply put with code examples:

  • ISO: First week starts with Monday and must contain the January 4th. The ISO calendar is already implemented in Python:

    >>> from datetime import date
    >>> date(2014, 12, 29).isocalendar()[:2]
    (2015, 1)
    
  • North American: First week starts with Sunday and must contain the January 1st. The following code is my modified version of Python’s ISO calendar implementation for the North American system:

    from datetime import date
    
    def week_from_date(date_object):
        date_ordinal = date_object.toordinal()
        year = date_object.year
        week = ((date_ordinal - _week1_start_ordinal(year)) // 7) + 1
        if week >= 52:
            if date_ordinal >= _week1_start_ordinal(year + 1):
                year += 1
                week = 1
        return year, week
    
    def _week1_start_ordinal(year):
        jan1 = date(year, 1, 1)
        jan1_ordinal = jan1.toordinal()
        jan1_weekday = jan1.weekday()
        week1_start_ordinal = jan1_ordinal - ((jan1_weekday + 1) % 7)
        return week1_start_ordinal
    
    >>> from datetime import date
    >>> week_from_date(date(2014, 12, 29))
    (2015, 1)
    
  • MMWR (CDC): First week starts with Sunday and must contain the January 4th. I created the epiweeks package specifically for this numbering system (also has support for the ISO system). Here is an example:
    >>> from datetime import date
    >>> from epiweeks import Week
    >>> Week.fromdate(date(2014, 12, 29))
    (2014, 53)
    
Answered By: dralshehri

Answer #8:

For the integer value of the instantaneous week of the year try:

import datetime
datetime.datetime.utcnow().isocalendar()[1]
Answered By: user2099484

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