How to find out what week number is current year on June 16th (wk24) with Python?
datetime.date has a
isocalendar() method, which returns a tuple containing the calendar week:
import datetime datetime.date(2010, 6, 16).isocalendar() 24
datetime.date.isocalendar() is an instance-method returning a tuple containing year, weeknumber and weekday in respective order for the given date instance.
You can get the week number directly from datetime as string.
import datetime datetime.date(2010, 6, 16).strftime("%V") '24'
Also you can get different “types” of the week number of the year changing the
strftime parameter for:
%U– Week number of the year (Sunday as the first day of the week) as a zero padded decimal number. All days in a new year preceding the first Sunday are considered to be in week 0. Examples: 00, 01, …, 53
%W– Week number of the year (Monday as the first day of the week) as a decimal number. All days in a new year preceding the first Monday are considered to be in week 0. Examples: 00, 01, …, 53
(Added in Python 3.6, backported to some distribution’s Python 2.7’s) Several additional directives not required by the C89 standard are included for convenience. These parameters all correspond to ISO 8601 date values. These may not be available on all platforms when used with the
%V– ISO 8601 week as a decimal number with Monday as the first day of the week. Week 01 is the week containing Jan 4. Examples: 01, 02, …, 53
I’ve found out about it from here. It worked for me in Python 2.7.6
date.isocalendar() is going to be the answer. This article explains the math behind ISO 8601 Calendar. Check out the date.isocalendar() portion of the datetime page of the Python documentation.
2010, 6, 16) wk = dt.isocalendar() 24dt = datetime.date(
.isocalendar() return a 3-tuple with (year, wk num, wk day).
dt.isocalendar() returns the year,
dt.isocalendar() returns the week number,
dt.isocalendar() returns the week day. Simple as can be.
Here’s another option:
import time from time import gmtime, strftime d = time.strptime("16 Jun 2010", "%d %b %Y") print(strftime(d, '%U'))
The ISO week suggested by others is a good one, but it might not fit your needs. It assumes each week begins with a Monday, which leads to some interesting anomalies at the beginning and end of the year.
If you’d rather use a definition that says week 1 is always January 1 through January 7, regardless of the day of the week, use a derivation like this:
2010,6,16) print(((testdate - datetime.datetime(testdate.year,1,1)).days // 7) + 1) 24testdate=datetime.datetime(
Generally to get the current week number (starts from Sunday):
from datetime import * today = datetime.today() print today.strftime("%U")
There are many systems for week numbering. The following are the most common systems simply put with code examples:
ISO: First week starts with Monday and must contain the January 4th. The ISO calendar is already implemented in Python:
from datetime import date date(2014, 12, 29).isocalendar()[:2] (2015, 1)
North American: First week starts with Sunday and must contain the January 1st. The following code is my modified version of Python’s ISO calendar implementation for the North American system:
from datetime import date def week_from_date(date_object): date_ordinal = date_object.toordinal() year = date_object.year week = ((date_ordinal - _week1_start_ordinal(year)) // 7) + 1 if week >= 52: if date_ordinal >= _week1_start_ordinal(year + 1): year += 1 week = 1 return year, week def _week1_start_ordinal(year): jan1 = date(year, 1, 1) jan1_ordinal = jan1.toordinal() jan1_weekday = jan1.weekday() week1_start_ordinal = jan1_ordinal - ((jan1_weekday + 1) % 7) return week1_start_ordinal
from datetime import date week_from_date(date(2014, 12, 29)) (2015, 1)
- MMWR (CDC): First week starts with Sunday and must contain the January 4th. I created the epiweeks package specifically for this numbering system (also has support for the ISO system). Here is an example:
from datetime import date from epiweeks import Week Week.fromdate(date(2014, 12, 29)) (2014, 53)
For the integer value of the instantaneous week of the year try:
import datetime datetime.datetime.utcnow().isocalendar()