Solving problem is about exposing yourself to as many situations as possible like How to format a floating number to fixed width in Python and practice these strategies over and over. With time, it becomes second nature and a natural way you approach any problems in general. Big or small, always start with a plan, use other strategies mentioned here till you are confident and ready to code the solution.

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How do I format a floating number to a fixed width with the following requirements:

- Leading zero if n < 1
- Add trailing decimal zero(s) to fill up fixed width
- Truncate decimal digits past fixed width
- Align all decimal points

For example:

```
% formatter something like '{:06}'
numbers = [23.23, 0.123334987, 1, 4.223, 9887.2]
for number in numbers:
print formatter.format(number)
```

The output would be like

```
23.2300
0.1233
1.0000
4.2230
9887.2000
```

##
Answer #1:

```
for x in numbers:
print "{:10.4f}".format(x)
```

prints

```
23.2300
0.1233
1.0000
4.2230
9887.2000
```

The format specifier inside the curly braces follows the Python format string syntax. Specifically, in this case, it consists of the following parts:

- The
*empty string*before the colon means “take the next provided argument to`format()`

” – in this case the`x`

as the only argument. - The
`10.4f`

part after the colon is the format specification. - The
`f`

denotes fixed-point notation. - The
`10`

is the total width of the field being printed, lefted-padded by spaces. - The
`4`

is the number of digits after the decimal point.

##
Answer #2:

It has been a few years since this was answered, **but as of Python 3.6** (PEP498) you could use the new `f-strings`

:

```
numbers = [23.23, 0.123334987, 1, 4.223, 9887.2]
for number in numbers:
print(f'{number:9.4f}')
```

**Prints:**

```
23.2300
0.1233
1.0000
4.2230
9887.2000
```

##
Answer #3:

In python3 the following works:

```
>>> v=10.4
>>> print('% 6.2f' % v)
10.40
>>> print('% 12.1f' % v)
10.4
>>> print('%012.1f' % v)
0000000010.4
```

##
Answer #4:

See Python 3.x format string syntax:

```
IDLE 3.5.1
numbers = ['23.23', '.1233', '1', '4.223', '9887.2']
for x in numbers:
print('{0: >#016.4f}'. format(float(x)))
23.2300
0.1233
1.0000
4.2230
9887.2000
```

##
Answer #5:

You can also left pad with zeros. For example if you want `number`

to have 9 characters length, left padded with zeros use:

`print('{:09.3f}'.format(number))`

Thus, if `number = 4.656`

, the output is: `00004.656`

For your example the output will look like this:

```
numbers = [23.2300, 0.1233, 1.0000, 4.2230, 9887.2000]
for x in numbers:
print('{:010.4f}'.format(x))
```

prints:

```
00023.2300
00000.1233
00001.0000
00004.2230
09887.2000
```

One example where this may be useful is when you want to properly list filenames in alphabetical order. I noticed in some linux systems, the number is: 1,10,11,..2,20,21,…

Thus if you want to enforce the necessary numeric order in filenames, you need to left pad with the appropriate number of zeros.

##
Answer #6:

In Python 3.

```
GPA = 2.5
print(" %6.1f " % GPA)
```

`6.1f`

means after the dots 1 digits show if you print 2 digits after the dots you should only `%6.2f`

such that `%6.3f`

3 digits print after the point.

##
Answer #7:

This will print `76.66`

:

```
print("Number: ", f"{76.663254: .2f}")
```

##
Answer #8:

I needed something similar for arrays. That helped me

```
some_array_rounded=np.around(some_array, 5)
```