How to check if an object is a generator object in python?

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Question :

How to check if an object is a generator object in python?

In python, how do I check if an object is a generator object?

Trying this –

>>> type(myobject, generator)

gives the error –

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name 'generator' is not defined

(I know I can check if the object has a next method for it to be a generator, but I want some way using which I can determine the type of any object, not just generators.)

Answer #1:

You can use GeneratorType from types:

>>> import types
>>> types.GeneratorType
<class 'generator'>
>>> gen = (i for i in range(10))
>>> isinstance(gen, types.GeneratorType)
True
Answered By: utdemir

Answer #2:

You mean generator functions ? use inspect.isgeneratorfunction.

EDIT :

if you want a generator object you can use inspect.isgenerator as pointed out by JAB in his comment.

Answered By: mouad

Answer #3:

I think it is important to make distinction between generator functions and generators (generator function’s result):

>>> def generator_function():
...     yield 1
...     yield 2
...
>>> import inspect
>>> inspect.isgeneratorfunction(generator_function)
True

calling generator_function won’t yield normal result, it even won’t execute any code in the function itself, the result will be special object called generator:

>>> generator = generator_function()
>>> generator
<generator object generator_function at 0x10b3f2b90>

so it is not generator function, but generator:

>>> inspect.isgeneratorfunction(generator)
False

>>> import types
>>> isinstance(generator, types.GeneratorType)
True

and generator function is not generator:

>>> isinstance(generator_function, types.GeneratorType)
False

just for a reference, actual call of function body will happen by consuming generator, e.g.:

>>> list(generator)
[1, 2]

See also In python is there a way to check if a function is a “generator function” before calling it?

Answered By: Robert Lujo

Answer #4:

The inspect.isgenerator function is fine if you want to check for pure generators (i.e. objects of class “generator”). However it will return False if you check, for example, a izip iterable. An alternative way for checking for a generalised generator is to use this function:

def isgenerator(iterable):
    return hasattr(iterable,'__iter__') and not hasattr(iterable,'__len__')
Answered By: Luca Sbardella

Answer #5:

You could use the Iterator or more specifically, the Generator from the typing module.

from typing import Generator, Iterator
g = (i for i in range(1_000_000))
print(type(g))
print(isinstance(g, Generator))
print(isinstance(g, Iterator))

result:

<class 'generator'>
True
True
Answered By: user9074332

Answer #6:

>>> import inspect
>>> 
>>> def foo():
...   yield 'foo'
... 
>>> print inspect.isgeneratorfunction(foo)
True
Answered By: Corey Goldberg

Answer #7:

I know I can check if the object has a next method for it to be a generator, but I want some way using which I can determine the type of any object, not just generators.

Don’t do this. It’s simply a very, very bad idea.

Instead, do this:

try:
    # Attempt to see if you have an iterable object.
    for i in some_thing_which_may_be_a_generator:
        # The real work on `i`
except TypeError:
     # some_thing_which_may_be_a_generator isn't actually a generator
     # do something else

In the unlikely event that the body of the for loop also has TypeErrors, there are several choices: (1) define a function to limit the scope of the errors, or (2) use a nested try block.

Or (3) something like this to distinguish all of these TypeErrors which are floating around.

try:
    # Attempt to see if you have an iterable object.
    # In the case of a generator or iterator iter simply 
    # returns the value it was passed.
    iterator = iter(some_thing_which_may_be_a_generator)
except TypeError:
     # some_thing_which_may_be_a_generator isn't actually a generator
     # do something else
else:
    for i in iterator:
         # the real work on `i`

Or (4) fix the other parts of your application to provide generators appropriately. That’s often simpler than all of this.

Answered By: S.Lott

Answer #8:

If you are using tornado webserver or similar you might have found that server methods are actually generators and not methods. This makes it difficult to call other methods because yield is not working inside the method and therefore you need to start managing pools of chained generator objects. A simple method to manage pools of chained generators is to create a help function such as

def chainPool(*arg):
    for f in arg:
      if(hasattr(f,"__iter__")):
          for e in f:
             yield e
      else:
         yield f

Now writing chained generators such as

[x for x in chainPool(chainPool(1,2),3,4,chainPool(5,chainPool(6)))]

Produces output

[1, 2, 3, 4, 5, 6]

Which is probably what you want if your looking to use generators as a thread alternative or similar.

Answered By: user6830669

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