Question :
how do I use empty namespaces in an lxml xpath query?
I have an xml document in the following format:
<feed xmlns="http://www.w3.org/2005/Atom" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:gsa="http://schemas.google.com/gsa/2007">
...
<entry>
<id>https://ip.ad.dr.ess:8000/feeds/diagnostics/smb://ip.ad.dr.ess/path/to/file</id>
<updated>2011-11-07T21:32:39.795Z</updated>
<app:edited xmlns:app="http://purl.org/atom/app#">2011-11-07T21:32:39.795Z</app:edited>
<link rel="self" type="application/atom+xml" href="https://ip.ad.dr.ess:8000/feeds/diagnostics"/>
<link rel="edit" type="application/atom+xml" href="https://ip.ad.dr.ess:8000/feeds/diagnostics"/>
<gsa:content name="entryID">smb://ip.ad.dr.ess/path/to/directory</gsa:content>
<gsa:content name="numCrawledURLs">7</gsa:content>
<gsa:content name="numExcludedURLs">0</gsa:content>
<gsa:content name="type">DirectoryContentData</gsa:content>
<gsa:content name="numRetrievalErrors">0</gsa:content>
</entry>
<entry>
...
</entry>
...
</feed>
I need to retrieve all entry elements using xpath in lxml. My problem is that I can’t figure out how to use an empty namespace. I have tried the following examples, but none work. Please advise.
import lxml.etree as et
tree=et.fromstring(xml)
The various things I have tried are:
for node in tree.xpath('//entry'):
or
namespaces = {None:"http://www.w3.org/2005/Atom" ,"openSearch":"http://a9.com/-/spec/opensearchrss/1.0/" ,"gsa":"http://schemas.google.com/gsa/2007"}
for node in tree.xpath('//entry', namespaces=ns):
or
for node in tree.xpath('//"{http://www.w3.org/2005/Atom}entry""'):
