glob exclude pattern

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Question :

glob exclude pattern

I have a directory with a bunch of files inside: eee2314, asd3442 … and eph.

I want to exclude all files that start with eph with the glob function.

How can I do it?

Answer #1:

The pattern rules for glob are not regular expressions. Instead, they follow standard Unix path expansion rules. There are only a few special characters: two different wild-cards, and character ranges are supported [from pymotw: glob – Filename pattern matching].

So you can exclude some files with patterns.
For example to exclude manifests files (files starting with _) with glob, you can use:

files = glob.glob('files_path/[!_]*')
Answered By: Kenly

Answer #2:

You can deduct sets:

set(glob("*")) - set(glob("eph*"))
Answered By: neutrinus

Answer #3:

You can’t exclude patterns with the glob function, globs only allow for inclusion patterns. Globbing syntax is very limited (even a [!..] character class must match a character, so it is an inclusion pattern for every character that is not in the class).

You’ll have to do your own filtering; a list comprehension usually works nicely here:

files = [fn for fn in glob('somepath/*.txt') 
         if not os.path.basename(fn).startswith('eph')]
Answered By: Martijn Pieters

Answer #4:

Late to the game but you could alternatively just apply a python filter to the result of a glob:

files = glob.iglob('your_path_here')
files_i_care_about = filter(lambda x: not x.startswith("eph"), files)

or replacing the lambda with an appropriate regex search, etc…

EDIT: I just realized that if you’re using full paths the startswith won’t work, so you’d need a regex

In [10]: a
Out[10]: ['/some/path/foo', 'some/path/bar', 'some/path/eph_thing']

In [11]: filter(lambda x: not'/eph', x), a)
Out[11]: ['/some/path/foo', 'some/path/bar']
Answered By: K Raphael

Answer #5:

Compare with glob, I recommend pathlib, filter one pattern is very simple.

from pathlib import Path

p = Path(YOUR_PATH)
filtered = [x for x in p.glob("**/*") if not"eph")]

and if you want to filter more complex pattern, you can define a function to do that, just like:

def not_in_pattern(x):
    return (not"eph")) and not"epi")

filtered = [x for x in p.glob("**/*") if not_in_pattern(x)]

use that code, you can filter all files that start with eph or start with epi.

Answered By: Scott Ming

Answer #6:

How about skipping the particular file while iterating over all the files in the folder!
Below code would skip all excel files that start with ‘eph’

import glob
import re
for file in glob.glob('*.xlsx'):
    if re.match('eph.*.xlsx',file):
        #do your stuff here

This way you can use more complex regex patterns to include/exclude a particular set of files in a folder.

Answered By: Azhar Ansari

Answer #7:

More generally, to exclude files that don’t comply with some shell regexp, you could use module fnmatch:

import fnmatch

file_list = glob('somepath')    
for ind, ii in enumerate(file_list):
    if not fnmatch.fnmatch(ii, 'bash_regexp_with_exclude'):

The above will first generate a list from a given path and next pop out the files that won’t satisfy the regular expression with the desired constraint.

Answered By: Lord Henry Wotton

Answer #8:

As mentioned by the accepted answer, you can’t exclude patterns with glob, so the following is a method to filter your glob result.

The accepted answer is probably the best pythonic way to do things but if you think list comprehensions look a bit ugly and want to make your code maximally numpythonic anyway (like I did) then you can do this (but note that this is probably less efficient than the list comprehension method):

import glob

data_files = glob.glob("path_to_files/*.fits")

light_files = np.setdiff1d( data_files, glob.glob("*BIAS*"))
light_files = np.setdiff1d(light_files, glob.glob("*FLAT*"))

(In my case, I had some image frames, bias frames, and flat frames all in one directory and I just wanted the image frames)

Answered By: Ryan Farber

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