I have a directory with a bunch of files inside:
asd3442 … and
I want to exclude all files that start with
eph with the
How can I do it?
The pattern rules for glob are not regular expressions. Instead, they follow standard Unix path expansion rules. There are only a few special characters: two different wild-cards, and character ranges are supported [from pymotw: glob – Filename pattern matching].
So you can exclude some files with patterns.
For example to exclude manifests files (files starting with
_) with glob, you can use:
files = glob.glob('files_path/[!_]*')
You can deduct sets:
set(glob("*")) - set(glob("eph*"))
You can’t exclude patterns with the
glob function, globs only allow for inclusion patterns. Globbing syntax is very limited (even a
[!..] character class must match a character, so it is an inclusion pattern for every character that is not in the class).
You’ll have to do your own filtering; a list comprehension usually works nicely here:
files = [fn for fn in glob('somepath/*.txt') if not os.path.basename(fn).startswith('eph')]
Late to the game but you could alternatively just apply a python
filter to the result of a
files = glob.iglob('your_path_here') files_i_care_about = filter(lambda x: not x.startswith("eph"), files)
or replacing the lambda with an appropriate regex search, etc…
EDIT: I just realized that if you’re using full paths the
startswith won’t work, so you’d need a regex
In : a Out: ['/some/path/foo', 'some/path/bar', 'some/path/eph_thing'] In : filter(lambda x: not re.search('/eph', x), a) Out: ['/some/path/foo', 'some/path/bar']
glob, I recommend
pathlib, filter one pattern is very simple.
from pathlib import Path p = Path(YOUR_PATH) filtered = [x for x in p.glob("**/*") if not x.name.startswith("eph")]
and if you want to filter more complex pattern, you can define a function to do that, just like:
def not_in_pattern(x): return (not x.name.startswith("eph")) and not x.name.startswith("epi") filtered = [x for x in p.glob("**/*") if not_in_pattern(x)]
use that code, you can filter all files that start with
eph or start with
How about skipping the particular file while iterating over all the files in the folder!
Below code would skip all excel files that start with ‘eph’
import glob import re for file in glob.glob('*.xlsx'): if re.match('eph.*.xlsx',file): continue else: #do your stuff here print(file)
This way you can use more complex regex patterns to include/exclude a particular set of files in a folder.
More generally, to exclude files that don’t comply with some shell regexp, you could use module
import fnmatch file_list = glob('somepath') for ind, ii in enumerate(file_list): if not fnmatch.fnmatch(ii, 'bash_regexp_with_exclude'): file_list.pop(ind)
The above will first generate a list from a given path and next pop out the files that won’t satisfy the regular expression with the desired constraint.
As mentioned by the accepted answer, you can’t exclude patterns with glob, so the following is a method to filter your glob result.
The accepted answer is probably the best pythonic way to do things but if you think list comprehensions look a bit ugly and want to make your code maximally numpythonic anyway (like I did) then you can do this (but note that this is probably less efficient than the list comprehension method):
import glob data_files = glob.glob("path_to_files/*.fits") light_files = np.setdiff1d( data_files, glob.glob("*BIAS*")) light_files = np.setdiff1d(light_files, glob.glob("*FLAT*"))
(In my case, I had some image frames, bias frames, and flat frames all in one directory and I just wanted the image frames)