get python dictionary from string containing key value pairs

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Question :

get python dictionary from string containing key value pairs

i have a python string in the format:

str = "name: srek age :24 description: blah blah"

is there any way to convert it to dictionary that looks like

{'name': 'srek', 'age': '24', 'description': 'blah blah'}  

where each entries are (key,value) pairs taken from string. I tried splitting the string to list by

str.split()  

and then manually removing :, checking each tag name, adding to a dictionary. The drawback of this method is: this method is nasty, I have to manually remove : for each pair and if there is multi word ‘value’ in string (for example, blah blah for description), each word will be a separate entry in a list which is not desirable. Is there any Pythonic way of getting the dictionary (using python 2.7) ?

Asked By: srek

||

Answer #1:

>>> r = "name: srek age :24 description: blah blah"
>>> import re
>>> regex = re.compile(r"b(w+)s*:s*([^:]*)(?=s+w+s*:|$)")
>>> d = dict(regex.findall(r))
>>> d
{'age': '24', 'name': 'srek', 'description': 'blah blah'}

Explanation:

b           # Start at a word boundary
(w+)        # Match and capture a single word (1+ alnum characters)
s*:s*      # Match a colon, optionally surrounded by whitespace
([^:]*)      # Match any number of non-colon characters
(?=          # Make sure that we stop when the following can be matched:
 s+w+s*:  #  the next dictionary key
|            # or
 $           #  the end of the string
)            # End of lookahead
Answered By: Tim Pietzcker

Answer #2:

without re:

r = "name: srek age :24 description: blah blah cat: dog stack:overflow"
lis=r.split(':')
dic={}
try :
 for i,x in enumerate(reversed(lis)):
    i+=1
    slast=lis[-(i+1)]
    slast=slast.split()
    dic[slast[-1]]=x

    lis[-(i+1)]=" ".join(slast[:-1])
except IndexError:pass    
print(dic)

{'age': '24', 'description': 'blah blah', 'stack': 'overflow', 'name': 'srek', 'cat': 'dog'}
Answered By: Ashwini Chaudhary

Answer #3:

Other variation of Aswini program which display the dictionary in original order

import os
import shutil
mystr = "name: srek age :24 description: blah blah cat: dog stack:overflow"
mlist = mystr.split(':')
dict = {}
list1 = []
list2 = []
try:
 for i,x in enumerate(reversed(mlist)):
    i = i + 1
    slast = mlist[-(i+1)]
    cut = slast.split()
    cut2 = cut[-1]
    list1.insert(i,cut2)
    list2.insert(i,x)
    dict.update({cut2:x})
    mlist[-(i+1)] = " ".join(cut[0:-1])
except:
 pass   

rlist1 = list1[::-1]
rlist2= list2[::-1]

print zip(rlist1, rlist2)

Output

[('name', 'srek'), ('age', '24'), ('description', 'blah blah'), ('cat', 'dog'), ('stack', 'overflow')]

Answered By: Mirage

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