CSV read specific row

Answer #1:

You could use a list comprehension to filter the file like so:

with open('file.csv') as fd:
    reader=csv.reader(fd)
    interestingrows=[row for idx, row in enumerate(reader) if idx in (28,62)]
# now interestingrows contains the 28th and the 62th row after the header

Answer #2:

You simply skip the necessary number of rows:

with open("test.csv", "rb") as infile:
    r = csv.reader(infile)
    for i in range(8): # count from 0 to 7
        next(r)     # and discard the rows
    row = next(r)   # "row" contains row number 9 now

Answer #3:

Use list to grab all the rows at once as a list. Then access your target rows by their index/offset in the list. For example:

#!/usr/bin/env python

import csv

with open('source.csv') as csv_file:
    csv_reader = csv.reader(csv_file)
    rows = list(csv_reader)

    print(rows[8])
    print(rows[22])

Answer #4:

You could read all of them and then use normal lists to find them.

with open('bigfile.csv','rb') as longishfile:
    reader=csv.reader(longishfile)
    rows=[r for r in reader]
print row[9]
print row[88]

If you have a massive file, this can kill your memory but if the file’s got less than 10,000 lines you shouldn’t run into any big slowdowns.

Answer #5:

You can do something like this :

with open('raw_data.csv') as csvfile:
    readCSV = list(csv.reader(csvfile, delimiter=','))
    row_you_want = readCSV[index_of_row_you_want]