Convert datetime object to a String of date only in Python

Answer #1:

You can use strftime to help you format your date.

E.g.,

import datetime
t = datetime.datetime(2012, 2, 23, 0, 0)
t.strftime('%m/%d/%Y')

will yield:

'02/23/2012'

More information about formatting see here

Answer #2:

date and datetime objects (and time as well) support a mini-language to specify output, and there are two ways to access it:

• direct method call: dt.strftime('format here')
• format method (python 2.6+): '{:format here}'.format(dt)
• f-strings (python 3.6+): f'{dt:format here}'

So your example could look like:

• dt.strftime('The date is %b %d, %Y')
• 'The date is {:%b %d, %Y}'.format(dt)
• f'The date is {dt:%b %d, %Y}'

In all three cases the output is:

The date is Feb 23, 2012

For completeness’ sake: you can also directly access the attributes of the object, but then you only get the numbers:

'The date is %s/%s/%s' % (dt.month, dt.day, dt.year)
# The date is 02/23/2012

The time taken to learn the mini-language is worth it.

For reference, here are the codes used in the mini-language:

• %a Weekday as locale’s abbreviated name.
• %A Weekday as locale’s full name.
• %w Weekday as a decimal number, where 0 is Sunday and 6 is Saturday.
• %d Day of the month as a zero-padded decimal number.
• %b Month as locale’s abbreviated name.
• %B Month as locale’s full name.
• %m Month as a zero-padded decimal number. 01, …, 12
• %y Year without century as a zero-padded decimal number. 00, …, 99
• %Y Year with century as a decimal number. 1970, 1988, 2001, 2013
• %H Hour (24-hour clock) as a zero-padded decimal number. 00, …, 23
• %I Hour (12-hour clock) as a zero-padded decimal number. 01, …, 12
• %p Locale’s equivalent of either AM or PM.
• %M Minute as a zero-padded decimal number. 00, …, 59
• %S Second as a zero-padded decimal number. 00, …, 59
• %f Microsecond as a decimal number, zero-padded on the left. 000000, …, 999999
• %z UTC offset in the form +HHMM or -HHMM (empty if naive), +0000, -0400, +1030
• %Z Time zone name (empty if naive), UTC, EST, CST
• %j Day of the year as a zero-padded decimal number. 001, …, 366
• %U Week number of the year (Sunday is the first) as a zero padded decimal number.
• %W Week number of the year (Monday is first) as a decimal number.
• %c Locale’s appropriate date and time representation.
• %x Locale’s appropriate date representation.
• %X Locale’s appropriate time representation.
• %% A literal ‘%’ character.

Answer #3:

Another option:

import datetime
now=datetime.datetime.now()
now.isoformat()
# ouptut --> '2016-03-09T08:18:20.860968'

Answer #4:

You could use simple string formatting methods:

>>> dt = datetime.datetime(2012, 2, 23, 0, 0)
>>> '{0.month}/{0.day}/{0.year}'.format(dt)
'2/23/2012'
>>> '%s/%s/%s' % (dt.month, dt.day, dt.year)
'2/23/2012'

Answer #5:

type-specific formatting can be used as well:

t = datetime.datetime(2012, 2, 23, 0, 0)
"{:%m/%d/%Y}".format(t)

Output:

'02/23/2012'

Answer #6:

If you looking for a simple way of datetime to string conversion and can omit the format. You can convert datetime object to str and then use array slicing.

In [1]: from datetime import datetime

In [2]: now = datetime.now()

In [3]: str(now)
Out[3]: '2019-04-26 18:03:50.941332'

In [5]: str(now)[:10]
Out[5]: '2019-04-26'

In [6]: str(now)[:19]
Out[6]: '2019-04-26 18:03:50'

But note the following thing. If other solutions will rise an AttributeError when the variable is None in this case you will receive a 'None' string.

In [9]: str(None)[:19]
Out[9]: 'None'

Answer #7:

If you want the time as well, just go with

datetime.datetime.now().__str__()

Prints 2019-07-11 19:36:31.118766 in console for me

Answer #8:

It is possible to convert a datetime object into a string by working directly with the components of the datetime object.

from datetime import date  

myDate = date.today()    
#print(myDate) would output 2017-05-23 because that is today
#reassign the myDate variable to myDate = myDate.month 
#then you could print(myDate.month) and you would get 5 as an integer
dateStr = str(myDate.month)+ "/" + str(myDate.day) + "/" + str(myDate.year)    
# myDate.month is equal to 5 as an integer, i use str() to change it to a 
# string I add(+)the "/" so now I have "5/" then myDate.day is 23 as
# an integer i change it to a string with str() and it is added to the "5/"   
# to get "5/23" and then I add another "/" now we have "5/23/" next is the 
# year which is 2017 as an integer, I use the function str() to change it to 
# a string and add it to the rest of the string.  Now we have "5/23/2017" as 
# a string. The final line prints the string.

print(dateStr)  

Output –> 5/23/2017