Assign output of os.system to a variable and prevent it from being displayed on the screen [duplicate]

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Assign output of os.system to a variable and prevent it from being displayed on the screen [duplicate]

I want to assign the output of a command I run using os.system to a variable and prevent it from being output to the screen. But, in the below code ,the output is sent to the screen and the value printed for var is 0, which I guess signifies whether the command ran successfully or not. Is there any way to assign the command output to the variable and also stop it from being displayed on the screen?

var = os.system("cat /etc/services")
print var #Prints 0
Asked By: John

||

Answer #1:

From “Equivalent of Bash Backticks in Python“, which I asked a long time ago, what you may want to use is popen:

os.popen('cat /etc/services').read()

From the docs for Python 3.6,

This is implemented using subprocess.Popen; see that class’s
documentation for more powerful ways to manage and communicate with
subprocesses.


Here’s the corresponding code for subprocess:

import subprocess
proc = subprocess.Popen(["cat", "/etc/services"], stdout=subprocess.PIPE, shell=True)
(out, err) = proc.communicate()
print "program output:", out
Answered By: Chris Bunch

Answer #2:

You might also want to look at the subprocess module, which was built to replace the whole family of Python popen-type calls.

import subprocess
output = subprocess.check_output("cat /etc/services", shell=True)

The advantage it has is that there is a ton of flexibility with how you invoke commands, where the standard in/out/error streams are connected, etc.

Answered By: Walter Mundt

Answer #3:

The commands module is a reasonably high-level way to do this:

import commands
status, output = commands.getstatusoutput("cat /etc/services")

status is 0, output is the contents of /etc/services.

Answered By: ianmclaury

Answer #4:

For python 3.5+ it is recommended that you use the run function from the subprocess module. This returns a CompletedProcess object, from which you can easily obtain the output as well as return code. Since you are only interested in the output, you can write a utility wrapper like this.

from subprocess import PIPE, run
def out(command):
    result = run(command, stdout=PIPE, stderr=PIPE, universal_newlines=True, shell=True)
    return result.stdout
my_output = out("echo hello world")
# Or
my_output = out(["echo", "hello world"])
Answered By: Chiel ten Brinke

Answer #5:

I know this has already been answered, but I wanted to share a potentially better looking way to call Popen via the use of from x import x and functions:

from subprocess import PIPE, Popen
def cmdline(command):
    process = Popen(
        args=command,
        stdout=PIPE,
        shell=True
    )
    return process.communicate()[0]
print cmdline("cat /etc/services")
print cmdline('ls')
print cmdline('rpm -qa | grep "php"')
print cmdline('nslookup google.com')
Answered By: Vasili Syrakis

Answer #6:

i do it with os.system temp file:

import tempfile,os
def readcmd(cmd):
    ftmp = tempfile.NamedTemporaryFile(suffix='.out', prefix='tmp', delete=False)
    fpath = ftmp.name
    if os.name=="nt":
        fpath = fpath.replace("/","\") # forwin
    ftmp.close()
    os.system(cmd + " > " + fpath)
    data = ""
    with open(fpath, 'r') as file:
        data = file.read()
        file.close()
    os.remove(fpath)
    return data
Answered By: lexa-b

Answer #7:

Python 2.6 and 3 specifically say to avoid using PIPE for stdout and stderr.

The correct way is

import subprocess
# must create a file object to store the output. Here we are getting
# the ssid we are connected to
outfile = open('/tmp/ssid', 'w');
status = subprocess.Popen(["iwgetid"], bufsize=0, stdout=outfile)
outfile.close()
# now operate on the file
Answered By: Kearney Taaffe

Answer #8:

from os import system, remove
from uuid import uuid4
def bash_(shell_command: str) -> tuple:
    """
    :param shell_command: your shell command
    :return: ( 1 | 0, stdout)
    """
    logfile: str = '/tmp/%s' % uuid4().hex
    err: int = system('%s &> %s' % (shell_command, logfile))
    out: str = open(logfile, 'r').read()
    remove(logfile)
    return err, out
# Example: 
print(bash_('cat /usr/bin/vi | wc -l'))
>>> (0, '3296n')```
Answered By: lestat_kim

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